Javoblari bilan test
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Tenglamani yeching: \( \log_2(x^2 - 4x + 5) = 1 \).
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Ifodani soddalashtiring: \( \frac{x^3 - 27}{x^2 - 9} \).
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Tengsizlikni yeching: \( |2x - 5| < 3 \).
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Funksiya aniqlanish sohasini toping: \( f(x) = \sqrt{9 - x^2} \).
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Tenglamani yeching: \( 3^{2x} - 4 \cdot 3^x + 3 = 0 \).
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Arifmetik progressiyada a₁ = 5, d = 3 boʻlsa, a₁₀ ni toping.
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Geometrik progressiyada b₁ = 2, q = 3 boʻlsa, b₅ ni toping.
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Tenglamani yeching: \( \sin x = \frac{1}{2} \), \( 0 \leq x \leq 2\pi \).
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Ifodani hisoblang: \( \lim_{x \to 2} \frac{x^2 - 4}{x - 2} \).
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Funksiyaning hosilasini toping: \( f(x) = x^3 - 3x^2 + 2 \).
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Tenglamani yeching: \( \sqrt{x + 3} = x - 3 \).
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Ifodani soddalashtiring: \( \frac{2^{n+3} - 2^{n+1}}{2^n} \).
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Tengsizlikni yeching: \( x^2 - 5x + 6 > 0 \).
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Funksiyaning eng kichik qiymatini toping: \( f(x) = x^2 - 4x + 5 \).
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Tenglamani yeching: \( \log_3(x - 1) + \log_3(x + 1) = 1 \).
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Ifodani hisoblang: \( \int_0^1 (2x + 3) \, dx \).
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Tenglamani yeching: \( 2\cos^2 x - \cos x - 1 = 0 \), \( 0 \leq x \leq 2\pi \).
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Arifmetik progressiyaning birinchi 10 ta hadi yigʻindisi 120, birinchi hadi 3 boʻlsa, ayirmasini toping.
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Tenglamani yeching: \( \frac{x}{x-2} + \frac{3}{x+2} = \frac{8}{x^2 - 4} \).
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Ifodani soddalashtiring: \( \frac{\sqrt{50} - \sqrt{18}}{\sqrt{2}} \).
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Tengsizlikni yeching: \( \frac{x-1}{x+2} \leq 0 \).
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Funksiyaning oʻsish oraligʻini toping: \( f(x) = x^3 - 6x^2 + 9x + 1 \).
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Tenglamani yeching: \( 4^{x-1} = 8^{x+2} \).
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Ifodani hisoblang: \( \log_5 125 + \log_2 16 - \log_3 9 \).
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Tenglamani yeching: \( \sqrt{2x + 5} - \sqrt{x - 1} = 2 \).
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Geometrik progressiyaning birinchi 5 ta hadi yigʻindisi 62, maxraji 2 boʻlsa, birinchi hadini toping.
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Tenglamani yeching: \( \tan x = \sqrt{3} \), \( 0 \leq x \leq 2\pi \).
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Ifodani hisoblang: \( \lim_{x \to \infty} \frac{3x^2 + 2x - 1}{x^2 - 4} \).
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Funksiyaning ikkinchi tartibli hosilasini toping: \( f(x) = \sin x + \cos x \).
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Tengsizlikni yeching: \( \log_{\frac{1}{2}}(x - 1) > 2 \).